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10001247633 = 34139497861
BaseRepresentation
bin10010101000001111…
…01110110110010001
3221211000010000120000
421110013232312101
5130440304411013
64332225240213
7502561126236
oct112407566621
927730100500
1010001247633
114272497413
121b31493069
13c35036310
146ac3a978d
153d8057973
hex2541eed91

10001247633 has 20 divisors (see below), whose sum is σ = 16089378228. Its totient is φ = 6154613280.

The previous prime is 10001247631. The next prime is 10001247701. The reversal of 10001247633 is 33674210001.

10001247633 is a `hidden beast` number, since 1 + 0 + 0 + 0 + 1 + 24 + 7 + 633 = 666.

10001247633 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 5651581329 + 4349666304 = 75177^2 + 65952^2 .

It is not a de Polignac number, because 10001247633 - 21 = 10001247631 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 10001247597 and 10001247606.

It is not an unprimeable number, because it can be changed into a prime (10001247631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 4747878 + ... + 4749983.

Almost surely, 210001247633 is an apocalyptic number.

10001247633 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10001247633 is a deficient number, since it is larger than the sum of its proper divisors (6088130595).

10001247633 is an equidigital number, since it uses as much as digits as its factorization.

10001247633 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9497886 (or 9497877 counting only the distinct ones).

The product of its (nonzero) digits is 3024, while the sum is 27.

Adding to 10001247633 its reverse (33674210001), we get a palindrome (43675457634).

The spelling of 10001247633 in words is "ten billion, one million, two hundred forty-seven thousand, six hundred thirty-three".

Divisors: 1 3 9 13 27 39 81 117 351 1053 9497861 28493583 85480749 123472193 256442247 370416579 769326741 1111249737 3333749211 10001247633