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100013100000 = 253551130307
BaseRepresentation
bin101110100100100111…
…1101100101111100000
3100120011002021220001220
41131021033230233200
53114311323200000
6113540111455040
710140263215632
oct1351117545740
9316132256056
10100013100000
1139462873350
1217472227480
13957b448318
144baaab0a52
1529054761a0
hex17493ecbe0

100013100000 has 288 divisors, whose sum is σ = 357990337152. Its totient is φ = 24244800000.

The previous prime is 100013099951. The next prime is 100013100001. The reversal of 100013100000 is 1310001.

It is a super-2 number, since 2×1000131000002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (6).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100013100001) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3284847 + ... + 3315153.

It is an arithmetic number, because the mean of its divisors is an integer number (1243022004).

Almost surely, 2100013100000 is an apocalyptic number.

100013100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100013100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (178995168576).

100013100000 is an abundant number, since it is smaller than the sum of its proper divisors (257977237152).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100013100000 is an equidigital number, since it uses as much as digits as its factorization.

100013100000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30356 (or 30328 counting only the distinct ones).

The product of its (nonzero) digits is 3, while the sum is 6.

Adding to 100013100000 its reverse (1310001), we get a palindrome (100014410001).

The spelling of 100013100000 in words is "one hundred billion, thirteen million, one hundred thousand".