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100013120131200 = 27352171439425869
BaseRepresentation
bin10110101111011000011110…
…011111111001000010000000
3111010010011100022011020202220
4112233120132133321002000
5101102103332223144300
6552413220524411040
730031465231335513
oct2657303637710200
9433104308136686
10100013120131200
112995a364a82a11
12b2732676a6a80
1343a62733894a3
141a9a9374ccd7a
15b86886550da0
hex5af61e7f9080

100013120131200 has 384 divisors, whose sum is σ = 349038963648000. Its totient is φ = 25083829616640.

The previous prime is 100013120131073. The next prime is 100013120131213. The reversal of 100013120131200 is 2131021310001.

It is a happy number.

100013120131200 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 100013120131200.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 234631866 + ... + 235057734.

It is an arithmetic number, because the mean of its divisors is an integer number (908955634500).

Almost surely, 2100013120131200 is an apocalyptic number.

100013120131200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100013120131200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (174519481824000).

100013120131200 is an abundant number, since it is smaller than the sum of its proper divisors (249025843516800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100013120131200 is a wasteful number, since it uses less digits than its factorization.

100013120131200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 427352 (or 427335 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 100013120131200 its reverse (2131021310001), we get a palindrome (102144141441201).

The spelling of 100013120131200 in words is "one hundred trillion, thirteen billion, one hundred twenty million, one hundred thirty-one thousand, two hundred".