10001321335 has 4 divisors (see below), whose sum is σ = 12001585608. Its totient is φ = 8001057064.

The previous prime is 10001321299. The next prime is 10001321389. The reversal of 10001321335 is 53312310001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53312310001 = 277 ⋅192463213.

It is a cyclic number.

It is not a de Polignac number, because 10001321335 - 2¹⁷ = 10001190263 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000132129 + ... + 1000132138.

It is an arithmetic number, because the mean of its divisors is an integer number (3000396402).

Almost surely, 2^10001321335 is an apocalyptic number.

10001321335 is a deficient number, since it is larger than the sum of its proper divisors (2000264273).

10001321335 is an equidigital number, since it uses as much as digits as its factorization.

10001321335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2000264272.

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 10001321335 its reverse (53312310001), we get a palindrome (63313631336).

The spelling of 10001321335 in words is "ten billion, one million, three hundred twenty-one thousand, three hundred thirty-five".