1000133111 has 2 divisors, whose sum is σ = 1000133112. Its totient is φ = 1000133110.

The previous prime is 1000133093. The next prime is 1000133149. The reversal of 1000133111 is 1113310001.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1000133111 - 2¹⁸ = 999870967 is a prime.

It is a super-3 number, since 3×1000133111³ (a number of 28 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1000133092 and 1000133101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000133011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500066555 + 500066556.

It is an arithmetic number, because the mean of its divisors is an integer number (500066556).

Almost surely, 2^1000133111 is an apocalyptic number.

1000133111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000133111 is an equidigital number, since it uses as much as digits as its factorization.

1000133111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 11.

The square root of 1000133111 is about 31624.8812013579. The cubic root of 1000133111 is about 1000.0443683648.

Adding to 1000133111 its reverse (1113310001), we get a palindrome (2113443112).

The spelling of 1000133111 in words is "one billion, one hundred thirty-three thousand, one hundred eleven".