Base | Representation |
---|---|
bin | 11101000110111001010… |
… | …00011100101010111111 |
3 | 10112121112001120111120121 |
4 | 32203130220130222333 |
5 | 112341233301102031 |
6 | 2043242154355411 |
7 | 132154152522325 |
oct | 16433450345277 |
9 | 3477461514517 |
10 | 1000134003391 |
11 | 3561776316a6 |
12 | 1419baa2bb67 |
13 | 73409c865a3 |
14 | 3659a169d15 |
15 | 1b0383d6011 |
hex | e8dca1cabf |
1000134003391 has 2 divisors, whose sum is σ = 1000134003392. Its totient is φ = 1000134003390.
The previous prime is 1000134003389. The next prime is 1000134003419. The reversal of 1000134003391 is 1933004310001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1000134003391 - 21 = 1000134003389 is a prime.
Together with 1000134003389, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000134003331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500067001695 + 500067001696.
It is an arithmetic number, because the mean of its divisors is an integer number (500067001696).
Almost surely, 21000134003391 is an apocalyptic number.
1000134003391 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000134003391 is an equidigital number, since it uses as much as digits as its factorization.
1000134003391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 1000134003391 its reverse (1933004310001), we get a palindrome (2933138313392).
The spelling of 1000134003391 in words is "one trillion, one hundred thirty-four million, three thousand, three hundred ninety-one".
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