Base | Representation |
---|---|
bin | 1001000110001101101000… |
… | …0111101100001001111000 |
3 | 1022102012210111120221101021 |
4 | 2101203122013230021320 |
5 | 2302334244342022130 |
6 | 33135002454232224 |
7 | 2051434251235540 |
oct | 221433207541170 |
9 | 38365714527337 |
10 | 10002343314040 |
11 | 3206a740495a0 |
12 | 1156630655674 |
13 | 5772a878778c |
14 | 26818a434320 |
15 | 1252b5a1d37a |
hex | 918da1ec278 |
10002343314040 has 512 divisors, whose sum is σ = 30032442316800. Its totient is φ = 2902376448000.
The previous prime is 10002343314017. The next prime is 10002343314059. The reversal of 10002343314040 is 4041334320001.
It is a super-2 number, since 2×100023433140402 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10002343313996 and 10002343314014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 4628570560 + ... + 4628572720.
It is an arithmetic number, because the mean of its divisors is an integer number (58657113900).
Almost surely, 210002343314040 is an apocalyptic number.
10002343314040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 10002343314040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15016221158400).
10002343314040 is an abundant number, since it is smaller than the sum of its proper divisors (20030099002760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10002343314040 is a wasteful number, since it uses less digits than its factorization.
10002343314040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3127 (or 3123 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 10002343314040 its reverse (4041334320001), we get a palindrome (14043677634041).
The spelling of 10002343314040 in words is "ten trillion, two billion, three hundred forty-three million, three hundred fourteen thousand, forty".
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