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1000340201311 = 1128267274391
BaseRepresentation
bin11101000111010001110…
…11000001111101011111
310112122001102120102221121
432203220323001331133
5112342144042420221
62043314442111411
7132162235262413
oct16435073017537
93478042512847
101000340201311
11356272a68200
12141a57aab567
13734409009a9
14365b96c2d43
151b04b566a41
hexe8e8ec1f5f

1000340201311 has 6 divisors (see below), whose sum is σ = 1099547494136. Its totient is φ = 909400182900.

The previous prime is 1000340201279. The next prime is 1000340201347. The reversal of 1000340201311 is 1131020430001.

It is not a de Polignac number, because 1000340201311 - 25 = 1000340201279 is a prime.

It is a super-2 number, since 2×10003402013112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1000340201411) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 4133637075 + ... + 4133637316.

Almost surely, 21000340201311 is an apocalyptic number.

1000340201311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1000340201311 is a deficient number, since it is larger than the sum of its proper divisors (99207292825).

1000340201311 is an equidigital number, since it uses as much as digits as its factorization.

1000340201311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8267274413 (or 8267274402 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1000340201311 its reverse (1131020430001), we get a palindrome (2131360631312).

The spelling of 1000340201311 in words is "one trillion, three hundred forty million, two hundred one thousand, three hundred eleven".

Divisors: 1 11 121 8267274391 90940018301 1000340201311