1000401001312 has 24 divisors (see below), whose sum is σ = 1969816968000. Its totient is φ = 500130025344.

The previous prime is 1000401001283. The next prime is 1000401001349. The reversal of 1000401001312 is 2131001040001.

It is a junction number, because it is equal to n+sod(n) for n = 1000401001292 and 1000401001301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1971312 + ... + 2426287.

It is an arithmetic number, because the mean of its divisors is an integer number (82075707000).

Almost surely, 2^{1000401001312} is an apocalyptic number.

It is an amenable number.

1000401001312 is a deficient number, since it is larger than the sum of its proper divisors (969415966688).

1000401001312 is an equidigital number, since it uses as much as digits as its factorization.

1000401001312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4404718 (or 4404710 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1000401001312 its reverse (2131001040001), we get a palindrome (3131402041313).

The spelling of 1000401001312 in words is "one trillion, four hundred one million, one thousand, three hundred twelve".