Base | Representation |
---|---|
bin | 11101000111011001001… |
… | …00001011100100001100 |
3 | 10112122012200120121022022 |
4 | 32203230210023210030 |
5 | 112342310214221304 |
6 | 2043324504105312 |
7 | 132163606626536 |
oct | 16435444134414 |
9 | 3478180517268 |
10 | 1000401320204 |
11 | 3562a4512790 |
12 | 141a74465238 |
13 | 73450480010 |
14 | 365c3872856 |
15 | 1b051adaebe |
hex | e8ec90b90c |
1000401320204 has 48 divisors (see below), whose sum is σ = 2062983342336. Its totient is φ = 418480603200.
The previous prime is 1000401320201. The next prime is 1000401320209. The reversal of 1000401320204 is 4020231040001.
It is a super-3 number, since 3×10004013202043 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (1000401320201) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2452592 + ... + 2831255.
It is an arithmetic number, because the mean of its divisors is an integer number (42978819632).
Almost surely, 21000401320204 is an apocalyptic number.
It is an amenable number.
1000401320204 is an abundant number, since it is smaller than the sum of its proper divisors (1062582022132).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1000401320204 is a wasteful number, since it uses less digits than its factorization.
1000401320204 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5284206 (or 5284204 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 1000401320204 its reverse (4020231040001), we get a palindrome (5020632360205).
The spelling of 1000401320204 in words is "one trillion, four hundred one million, three hundred twenty thousand, two hundred four".
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