Base | Representation |
---|---|
bin | 10110101111110010011100… |
… | …100101011100111100110011 |
3 | 111010012211022200001201100122 |
4 | 112233302130211130330303 |
5 | 101103032434330301120 |
6 | 552434111533040455 |
7 | 30033503241501131 |
oct | 2657623445347463 |
9 | 433184280051318 |
10 | 100041005322035 |
11 | 29970174493578 |
12 | b27874a32612b |
13 | 43a8a98579bcb |
14 | 1a9c020b14751 |
15 | b87469689a25 |
hex | 5afc9c95cf33 |
100041005322035 has 16 divisors (see below), whose sum is σ = 125356399122240. Its totient is φ = 76499545879680.
The previous prime is 100041005321977. The next prime is 100041005322043. The reversal of 100041005322035 is 530223500140001.
It is a happy number.
It is not a de Polignac number, because 100041005322035 - 222 = 100041001127731 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100041005321995 and 100041005322013.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 304216976 + ... + 304545645.
It is an arithmetic number, because the mean of its divisors is an integer number (7834774945140).
Almost surely, 2100041005322035 is an apocalyptic number.
100041005322035 is a deficient number, since it is larger than the sum of its proper divisors (25315393800205).
100041005322035 is a wasteful number, since it uses less digits than its factorization.
100041005322035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 608764078.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 100041005322035 its reverse (530223500140001), we get a palindrome (630264505462036).
The spelling of 100041005322035 in words is "one hundred trillion, forty-one billion, five million, three hundred twenty-two thousand, thirty-five".
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