10004402333133 has 12 divisors (see below), whose sum is σ = 15562403629500. Its totient is φ = 6156555281856.

The previous prime is 10004402333083. The next prime is 10004402333141. The reversal of 10004402333133 is 33133320440001.

10004402333133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 1306545013764 + 8697857319369 = 1143042^2 + 2949213^2 .

It is not a de Polignac number, because 10004402333133 - 2⁴⁰ = 8904890705357 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10004402333097 and 10004402333106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10004402333173) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 42753856008 + ... + 42753856241.

It is an arithmetic number, because the mean of its divisors is an integer number (1296866969125).

Almost surely, 2^{10004402333133} is an apocalyptic number.

10004402333133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10004402333133 is a deficient number, since it is larger than the sum of its proper divisors (5558001296367).

10004402333133 is a wasteful number, since it uses less digits than its factorization.

10004402333133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85507712268 (or 85507712265 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 27.

Adding to 10004402333133 its reverse (33133320440001), we get a palindrome (43137722773134).

The spelling of 10004402333133 in words is "ten trillion, four billion, four hundred two million, three hundred thirty-three thousand, one hundred thirty-three".