1001001101201 has 2 divisors, whose sum is σ = 1001001101202. Its totient is φ = 1001001101200.

The previous prime is 1001001101167. The next prime is 1001001101203. The reversal of 1001001101201 is 1021011001001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 915341860225 + 85659240976 = 956735^2 + 292676^2 .

It is an emirp because it is prime and its reverse (1021011001001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1001001101201 is a prime.

It is a super-2 number, since 2×1001001101201² (a number of 25 digits) contains 22 as substring.

Together with 1001001101203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1001001101203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500500550600 + 500500550601.

It is an arithmetic number, because the mean of its divisors is an integer number (500500550601).

Almost surely, 2^{1001001101201} is an apocalyptic number.

It is an amenable number.

1001001101201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001001101201 is an equidigital number, since it uses as much as digits as its factorization.

1001001101201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2, while the sum is 8.

Adding to 1001001101201 its reverse (1021011001001), we get a palindrome (2022012102202).

The spelling of 1001001101201 in words is "one trillion, one billion, one million, one hundred one thousand, two hundred one".