Base | Representation |
---|---|
bin | 1001000110101010001100… |
… | …1001101001011111000111 |
3 | 1022102221120212201111211211 |
4 | 2101222203021221133013 |
5 | 2303001000304440421 |
6 | 33142311403512251 |
7 | 2052125255514262 |
oct | 221524311513707 |
9 | 38387525644754 |
10 | 10010011015111 |
11 | 320a249291928 |
12 | 1158010528687 |
13 | 577c2b2015c3 |
14 | 2686b691bcd9 |
15 | 1255b3c799e1 |
hex | 91aa32697c7 |
10010011015111 has 2 divisors, whose sum is σ = 10010011015112. Its totient is φ = 10010011015110.
The previous prime is 10010011015097. The next prime is 10010011015127. The reversal of 10010011015111 is 11151011001001.
10010011015111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10010011015111 - 25 = 10010011015079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10010011015091 and 10010011015100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10010011015141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005005507555 + 5005005507556.
It is an arithmetic number, because the mean of its divisors is an integer number (5005005507556).
Almost surely, 210010011015111 is an apocalyptic number.
10010011015111 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010011015111 is an equidigital number, since it uses as much as digits as its factorization.
10010011015111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5, while the sum is 13.
Adding to 10010011015111 its reverse (11151011001001), we get a palindrome (21161022016112).
The spelling of 10010011015111 in words is "ten trillion, ten billion, eleven million, fifteen thousand, one hundred eleven".
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