Base | Representation |
---|---|
bin | 11101001000100000101… |
… | …00001111000100010111 |
3 | 10112200202111012120222102 |
4 | 32210100110033010113 |
5 | 112400022241320043 |
6 | 2043504211552315 |
7 | 132214512063212 |
oct | 16442024170427 |
9 | 3480674176872 |
10 | 1001001120023 |
11 | 356582044213 |
12 | 1420012bb69b |
13 | 73517808758 |
14 | 3663d3a6779 |
15 | 1b0895b96b8 |
hex | e91050f117 |
1001001120023 has 2 divisors, whose sum is σ = 1001001120024. Its totient is φ = 1001001120022.
The previous prime is 1001001120013. The next prime is 1001001120043. The reversal of 1001001120023 is 3200211001001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1001001120023 - 236 = 932281643287 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1001001119986 and 1001001120013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001001120013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500500560011 + 500500560012.
It is an arithmetic number, because the mean of its divisors is an integer number (500500560012).
Almost surely, 21001001120023 is an apocalyptic number.
1001001120023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001001120023 is an equidigital number, since it uses as much as digits as its factorization.
1001001120023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 1001001120023 its reverse (3200211001001), we get a palindrome (4201212121024).
The spelling of 1001001120023 in words is "one trillion, one billion, one million, one hundred twenty thousand, twenty-three".
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