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1001002222013 is a prime number
BaseRepresentation
bin11101001000100000110…
…00011100000110111101
310112200202120021120121212
432210100120130012331
5112400023032101023
62043504251334205
7132214524333053
oct16442030340675
93480676246555
101001002222013
11356582727152
12142001751365
1373517b03211
143663d5b21d3
151b089735e78
hexe91061c1bd

1001002222013 has 2 divisors, whose sum is σ = 1001002222014. Its totient is φ = 1001002222012.

The previous prime is 1001002222007. The next prime is 1001002222019. The reversal of 1001002222013 is 3102222001001.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (1001002222007) and next prime (1001002222019).

It can be written as a sum of positive squares in only one way, i.e., 897335609284 + 103666612729 = 947278^2 + 321973^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001002222013 - 220 = 1001001173437 is a prime.

It is a super-3 number, since 3×10010022220133 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001002222019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500501111006 + 500501111007.

It is an arithmetic number, because the mean of its divisors is an integer number (500501111007).

Almost surely, 21001002222013 is an apocalyptic number.

It is an amenable number.

1001002222013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001002222013 is an equidigital number, since it uses as much as digits as its factorization.

1001002222013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 1001002222013 its reverse (3102222001001), we get a palindrome (4103224223014).

The spelling of 1001002222013 in words is "one trillion, one billion, two million, two hundred twenty-two thousand, thirteen".