Base | Representation |
---|---|
bin | 10110110000101010010101… |
… | …110011000110000101101111 |
3 | 111010102120020021011001021222 |
4 | 112300222111303012011233 |
5 | 101110023342334000142 |
6 | 552521435121213555 |
7 | 30041026421364254 |
oct | 2660522563060557 |
9 | 433376207131258 |
10 | 100101021000047 |
11 | 299936717a9771 |
12 | b2882b94912bb |
13 | 43b1641336212 |
14 | 1aa0cb56c942b |
15 | b88ccd487bd2 |
hex | 5b0a95cc616f |
100101021000047 has 2 divisors, whose sum is σ = 100101021000048. Its totient is φ = 100101021000046.
The previous prime is 100101020999989. The next prime is 100101021000049. The reversal of 100101021000047 is 740000120101001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100101021000047 - 242 = 95702974488943 is a prime.
Together with 100101021000049, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 100101020999989 and 100101021000034.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100101021000049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050510500023 + 50050510500024.
It is an arithmetic number, because the mean of its divisors is an integer number (50050510500024).
Almost surely, 2100101021000047 is an apocalyptic number.
100101021000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
100101021000047 is an equidigital number, since it uses as much as digits as its factorization.
100101021000047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 100101021000047 its reverse (740000120101001), we get a palindrome (840101141101048).
The spelling of 100101021000047 in words is "one hundred trillion, one hundred one billion, twenty-one million, forty-seven", and thus it is an aban number.
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