100101102113 has 4 divisors (see below), whose sum is σ = 104453323968. Its totient is φ = 95748880260.

The previous prime is 100101102097. The next prime is 100101102131. The reversal of 100101102113 is 311201101001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100101102113 - 2⁴ = 100101102097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100101102094 and 100101102103.

It is not an unprimeable number, because it can be changed into a prime (100101122113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2176110893 + ... + 2176110938.

It is an arithmetic number, because the mean of its divisors is an integer number (26113330992).

Almost surely, 2^100101102113 is an apocalyptic number.

It is an amenable number.

100101102113 is a deficient number, since it is larger than the sum of its proper divisors (4352221855).

100101102113 is an equidigital number, since it uses as much as digits as its factorization.

100101102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4352221854.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 100101102113 its reverse (311201101001), we get a palindrome (411302203114).

The spelling of 100101102113 in words is "one hundred billion, one hundred one million, one hundred two thousand, one hundred thirteen".