100101121102121 has 2 divisors, whose sum is σ = 100101121102122. Its totient is φ = 100101121102120.

The previous prime is 100101121102093. The next prime is 100101121102123. The reversal of 100101121102121 is 121201121101001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96452257062121 + 3648864040000 = 9821011^2 + 1910200^2 .

It is an emirp because it is prime and its reverse (121201121101001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100101121102121 - 2³⁸ = 99826243195177 is a prime.

Together with 100101121102123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100101121102096 and 100101121102105.

It is not a weakly prime, because it can be changed into another prime (100101121102123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050560551060 + 50050560551061.

It is an arithmetic number, because the mean of its divisors is an integer number (50050560551061).

Almost surely, 2^{100101121102121} is an apocalyptic number.

It is an amenable number.

100101121102121 is a deficient number, since it is larger than the sum of its proper divisors (1).

100101121102121 is an equidigital number, since it uses as much as digits as its factorization.

100101121102121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 100101121102121 its reverse (121201121101001), we get a palindrome (221302242203122).

The spelling of 100101121102121 in words is "one hundred trillion, one hundred one billion, one hundred twenty-one million, one hundred two thousand, one hundred twenty-one".