1001111000051 has 2 divisors, whose sum is σ = 1001111000052. Its totient is φ = 1001111000050.

The previous prime is 1001111000017. The next prime is 1001111000063. The reversal of 1001111000051 is 1500001111001.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1500001111001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1001111000051 - 2¹⁴ = 1001110983667 is a prime.

It is a super-2 number, since 2×1001111000051² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1001110999996 and 1001111000041.

It is not a weakly prime, because it can be changed into another prime (1001111009051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500555500025 + 500555500026.

It is an arithmetic number, because the mean of its divisors is an integer number (500555500026).

Almost surely, 2^{1001111000051} is an apocalyptic number.

1001111000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001111000051 is an equidigital number, since it uses as much as digits as its factorization.

1001111000051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5, while the sum is 11.

Adding to 1001111000051 its reverse (1500001111001), we get a palindrome (2501112111052).

The spelling of 1001111000051 in words is "one trillion, one billion, one hundred eleven million, fifty-one", and thus it is an aban number.