100111200200113 has 4 divisors (see below), whose sum is σ = 101046818893680. Its totient is φ = 99175581506548.

The previous prime is 100111200200087. The next prime is 100111200200119. The reversal of 100111200200113 is 311002002111001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100111200200113 - 2⁹ = 100111200199601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100111200200093 and 100111200200102.

It is not an unprimeable number, because it can be changed into a prime (100111200200119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 467809346623 + ... + 467809346836.

It is an arithmetic number, because the mean of its divisors is an integer number (25261704723420).

Almost surely, 2^{100111200200113} is an apocalyptic number.

It is an amenable number.

100111200200113 is a deficient number, since it is larger than the sum of its proper divisors (935618693567).

100111200200113 is an equidigital number, since it uses as much as digits as its factorization.

100111200200113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 935618693566.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 100111200200113 its reverse (311002002111001), we get a palindrome (411113202311114).

The spelling of 100111200200113 in words is "one hundred trillion, one hundred eleven billion, two hundred million, two hundred thousand, one hundred thirteen".