100112000014111 has 2 divisors, whose sum is σ = 100112000014112. Its totient is φ = 100112000014110.

The previous prime is 100112000014097. The next prime is 100112000014129. The reversal of 100112000014111 is 111410000211001.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100112000014111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100112000014091 and 100112000014100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100112000014141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056000007055 + 50056000007056.

It is an arithmetic number, because the mean of its divisors is an integer number (50056000007056).

Almost surely, 2^{100112000014111} is an apocalyptic number.

100112000014111 is a deficient number, since it is larger than the sum of its proper divisors (1).

100112000014111 is an equidigital number, since it uses as much as digits as its factorization.

100112000014111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 100112000014111 its reverse (111410000211001), we get a palindrome (211522000225112).

The spelling of 100112000014111 in words is "one hundred trillion, one hundred twelve billion, fourteen thousand, one hundred eleven".