Base | Representation |
---|---|
bin | 1001000110101110101010… |
… | …1100110010101001100111 |
3 | 1022110001200112110220002122 |
4 | 2101223222230302221213 |
5 | 2303010430110110043 |
6 | 33143030444300155 |
7 | 2052200102636015 |
oct | 221535254625147 |
9 | 38401615426078 |
10 | 10011211410023 |
11 | 320a80493833a |
12 | 11582a654165b |
13 | 57808cb03755 |
14 | 26878c1118b5 |
15 | 125634342368 |
hex | 91aeab32a67 |
10011211410023 has 2 divisors, whose sum is σ = 10011211410024. Its totient is φ = 10011211410022.
The previous prime is 10011211409993. The next prime is 10011211410073. The reversal of 10011211410023 is 32001411211001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10011211410023 - 26 = 10011211409959 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10011211409983 and 10011211410010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10011211410073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005605705011 + 5005605705012.
It is an arithmetic number, because the mean of its divisors is an integer number (5005605705012).
Almost surely, 210011211410023 is an apocalyptic number.
10011211410023 is a deficient number, since it is larger than the sum of its proper divisors (1).
10011211410023 is an equidigital number, since it uses as much as digits as its factorization.
10011211410023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 10011211410023 its reverse (32001411211001), we get a palindrome (42012622621024).
The spelling of 10011211410023 in words is "ten trillion, eleven billion, two hundred eleven million, four hundred ten thousand, twenty-three".
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