Base | Representation |
---|---|
bin | 10110110000110100110000… |
… | …000111100110100111011011 |
3 | 111010110122002100102012001202 |
4 | 112300310300013212213123 |
5 | 101110214241200031021 |
6 | 552530524302104415 |
7 | 30041603433340601 |
oct | 2660646007464733 |
9 | 433418070365052 |
10 | 100112200002011 |
11 | 29998388a8836a |
12 | b28a4b927b10b |
13 | 43b2703375392 |
14 | 1aa1656273871 |
15 | b89234ad4a0b |
hex | 5b0d301e69db |
100112200002011 has 2 divisors, whose sum is σ = 100112200002012. Its totient is φ = 100112200002010.
The previous prime is 100112200002007. The next prime is 100112200002013. The reversal of 100112200002011 is 110200002211001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100112200002011 - 22 = 100112200002007 is a prime.
Together with 100112200002013, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 100112200001983 and 100112200002001.
It is not a weakly prime, because it can be changed into another prime (100112200002013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056100001005 + 50056100001006.
It is an arithmetic number, because the mean of its divisors is an integer number (50056100001006).
Almost surely, 2100112200002011 is an apocalyptic number.
100112200002011 is a deficient number, since it is larger than the sum of its proper divisors (1).
100112200002011 is an equidigital number, since it uses as much as digits as its factorization.
100112200002011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 100112200002011 its reverse (110200002211001), we get a palindrome (210312202213012).
The spelling of 100112200002011 in words is "one hundred trillion, one hundred twelve billion, two hundred million, two thousand, eleven".
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