Base | Representation |
---|---|
bin | 101110100111100110… |
… | …1001010110101010001 |
3 | 100120102001110102102210 |
4 | 1131033031022311101 |
5 | 3120012423200423 |
6 | 113554043102333 |
7 | 10142616211305 |
oct | 1351715126521 |
9 | 316361412383 |
10 | 100113100113 |
11 | 39504264974 |
12 | 1749b8119a9 |
13 | 959608bba0 |
14 | 4bba0a1d05 |
15 | 290e12ab93 |
hex | 174f34ad51 |
100113100113 has 64 divisors (see below), whose sum is σ = 154748772864. Its totient is φ = 57024000000.
The previous prime is 100113100111. The next prime is 100113100117. The reversal of 100113100113 is 311001311001.
It is not a de Polignac number, because 100113100113 - 21 = 100113100111 is a prime.
It is a super-2 number, since 2×1001131001132 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (100113100111) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 10106463 + ... + 10116363.
It is an arithmetic number, because the mean of its divisors is an integer number (2417949576).
Almost surely, 2100113100113 is an apocalyptic number.
100113100113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
100113100113 is a deficient number, since it is larger than the sum of its proper divisors (54635672751).
100113100113 is a wasteful number, since it uses less digits than its factorization.
100113100113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10186.
The product of its (nonzero) digits is 9, while the sum is 12.
Adding to 100113100113 its reverse (311001311001), we get a palindrome (411114411114).
The spelling of 100113100113 in words is "one hundred billion, one hundred thirteen million, one hundred thousand, one hundred thirteen".
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