100113103031 has 2 divisors, whose sum is σ = 100113103032. Its totient is φ = 100113103030.

The previous prime is 100113102983. The next prime is 100113103033. The reversal of 100113103031 is 130301311001.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (130301311001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100113103031 is a prime.

It is a super-2 number, since 2×100113103031² (a number of 23 digits) contains 22 as substring.

Together with 100113103033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100113102997 and 100113103015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100113103033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056551515 + 50056551516.

It is an arithmetic number, because the mean of its divisors is an integer number (50056551516).

Almost surely, 2^100113103031 is an apocalyptic number.

100113103031 is a deficient number, since it is larger than the sum of its proper divisors (1).

100113103031 is an equidigital number, since it uses as much as digits as its factorization.

100113103031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 100113103031 its reverse (130301311001), we get a palindrome (230414414032).

The spelling of 100113103031 in words is "one hundred billion, one hundred thirteen million, one hundred three thousand, thirty-one".