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1001132220113 = 2343527487831
BaseRepresentation
bin11101001000110000010…
…00010101111011010001
310112201002121220011111022
432210120020111323101
5112400304322020423
62043525213525225
7132220663315214
oct16443010257321
93481077804438
101001132220113
1135663a0476a3
121420391a3815
1373538a1ab7c
143665297177b
151b095d63dc8
hexe918215ed1

1001132220113 has 4 divisors (see below), whose sum is σ = 1044659707968. Its totient is φ = 957604732260.

The previous prime is 1001132220083. The next prime is 1001132220173. The reversal of 1001132220113 is 3110222311001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1001132220113 - 222 = 1001128025809 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1001132220091 and 1001132220100.

It is not an unprimeable number, because it can be changed into a prime (1001132220173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21763743893 + ... + 21763743938.

It is an arithmetic number, because the mean of its divisors is an integer number (261164926992).

Almost surely, 21001132220113 is an apocalyptic number.

It is an amenable number.

1001132220113 is a deficient number, since it is larger than the sum of its proper divisors (43527487855).

1001132220113 is an equidigital number, since it uses as much as digits as its factorization.

1001132220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43527487854.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1001132220113 its reverse (3110222311001), we get a palindrome (4111354531114).

The spelling of 1001132220113 in words is "one trillion, one billion, one hundred thirty-two million, two hundred twenty thousand, one hundred thirteen".

Divisors: 1 23 43527487831 1001132220113