1001202210011 has 2 divisors, whose sum is σ = 1001202210012. Its totient is φ = 1001202210010.

The previous prime is 1001202209957. The next prime is 1001202210013. The reversal of 1001202210011 is 1100122021001.

It is a strong prime.

It is an emirp because it is prime and its reverse (1100122021001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1001202210011 - 2¹⁴ = 1001202193627 is a prime.

Together with 1001202210013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1001202209974 and 1001202210001.

It is not a weakly prime, because it can be changed into another prime (1001202210013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500601105005 + 500601105006.

It is an arithmetic number, because the mean of its divisors is an integer number (500601105006).

Almost surely, 2^{1001202210011} is an apocalyptic number.

1001202210011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001202210011 is an equidigital number, since it uses as much as digits as its factorization.

1001202210011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 1001202210011 its reverse (1100122021001), we get a palindrome (2101324231012).

The spelling of 1001202210011 in words is "one trillion, one billion, two hundred two million, two hundred ten thousand, eleven".