100122010012067 has 2 divisors, whose sum is σ = 100122010012068. Its totient is φ = 100122010012066.

The previous prime is 100122010012007. The next prime is 100122010012069. The reversal of 100122010012067 is 760210010221001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100122010012067 is a prime.

It is a super-3 number, since 3×100122010012067³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 100122010012069, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (100122010012069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061005006033 + 50061005006034.

It is an arithmetic number, because the mean of its divisors is an integer number (50061005006034).

Almost surely, 2^{100122010012067} is an apocalyptic number.

100122010012067 is a deficient number, since it is larger than the sum of its proper divisors (1).

100122010012067 is an equidigital number, since it uses as much as digits as its factorization.

100122010012067 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 100122010012067 its reverse (760210010221001), we get a palindrome (860332020233068).

The spelling of 100122010012067 in words is "one hundred trillion, one hundred twenty-two billion, ten million, twelve thousand, sixty-seven".