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100122231300 = 2235271329312517
BaseRepresentation
bin101110100111111000…
…0000000001000000100
3100120102200122100001220
41131033300000020010
53120022242400200
6113555010520340
710143056631660
oct1351760001004
9316380570056
10100122231300
1139509431303
12174a28960b0
139597c38160
144bbb39b8a0
15290ed314a0
hex174fc00204

100122231300 has 288 divisors, whose sum is σ = 357783267072. Its totient is φ = 21050910720.

The previous prime is 100122231227. The next prime is 100122231301. The reversal of 100122231300 is 3132221001.

It is a super-2 number, since 2×1001222313002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 100122231300.

It is not an unprimeable number, because it can be changed into a prime (100122231301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 7992642 + ... + 8005158.

Almost surely, 2100122231300 is an apocalyptic number.

100122231300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100122231300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (178891633536).

100122231300 is an abundant number, since it is smaller than the sum of its proper divisors (257661035772).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100122231300 is a wasteful number, since it uses less digits than its factorization.

100122231300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12847 (or 12840 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 100122231300 its reverse (3132221001), we get a palindrome (103254452301).

The spelling of 100122231300 in words is "one hundred billion, one hundred twenty-two million, two hundred thirty-one thousand, three hundred".