10012234131135 has 24 divisors (see below), whose sum is σ = 17445400637184. Its totient is φ = 5311900825920.

The previous prime is 10012234131121. The next prime is 10012234131203. The reversal of 10012234131135 is 53113143221001.

10012234131135 is a `hidden beast` number, since 1 + 0 + 0 + 1 + 2 + 2 + 341 + 311 + 3 + 5 = 666.

It is not a de Polignac number, because 10012234131135 - 2⁵ = 10012234131103 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10012234131099 and 10012234131108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 582436672 + ... + 582453861.

It is an arithmetic number, because the mean of its divisors is an integer number (726891693216).

Almost surely, 2^{10012234131135} is an apocalyptic number.

10012234131135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

10012234131135 is a deficient number, since it is larger than the sum of its proper divisors (7433166506049).

10012234131135 is a wasteful number, since it uses less digits than its factorization.

10012234131135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1164890735 (or 1164890732 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 27.

Adding to 10012234131135 its reverse (53113143221001), we get a palindrome (63125377352136).

The spelling of 10012234131135 in words is "ten trillion, twelve billion, two hundred thirty-four million, one hundred thirty-one thousand, one hundred thirty-five".