Base | Representation |
---|---|
bin | 10110110001000111011001… |
… | …100001111101110001100100 |
3 | 111010112112202201120201222210 |
4 | 112301013121201331301210 |
5 | 101111031242331200200 |
6 | 552544035141523420 |
7 | 30043212544542432 |
oct | 2661073141756144 |
9 | 433475681521883 |
10 | 100132222131300 |
11 | 299a5922a51457 |
12 | b292366713570 |
13 | 43b45744ca668 |
14 | 1aa25d5479d52 |
15 | b89a07772650 |
hex | 5b11d987dc64 |
100132222131300 has 36 divisors (see below), whose sum is σ = 289715896034096. Its totient is φ = 26701925901600.
The previous prime is 100132222131299. The next prime is 100132222131307. The reversal of 100132222131300 is 3131222231001.
It is a super-3 number, since 3×1001322221313003 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (100132222131307) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 166887036586 + ... + 166887037185.
Almost surely, 2100132222131300 is an apocalyptic number.
100132222131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
100132222131300 is an abundant number, since it is smaller than the sum of its proper divisors (189583673902796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100132222131300 is a wasteful number, since it uses less digits than its factorization.
100132222131300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 333774073788 (or 333774073781 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 100132222131300 its reverse (3131222231001), we get a palindrome (103263444362301).
The spelling of 100132222131300 in words is "one hundred trillion, one hundred thirty-two billion, two hundred twenty-two million, one hundred thirty-one thousand, three hundred".
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