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100133000311 = 109918651379
BaseRepresentation
bin101110101000001100…
…1000101010001110111
3100120110102220110101011
41131100121011101313
53120033022002221
6114000033413051
710143250313341
oct1352031052167
9316412813334
10100133000311
1139514517213
12174a640a187
13959a238a56
144bbc9a2291
152910c5c1e1
hex1750645477

100133000311 has 4 divisors (see below), whose sum is σ = 101051651800. Its totient is φ = 99214348824.

The previous prime is 100133000251. The next prime is 100133000339. The reversal of 100133000311 is 113000331001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100133000311 - 211 = 100132998263 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100133000291 and 100133000300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100133000371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 459325581 + ... + 459325798.

It is an arithmetic number, because the mean of its divisors is an integer number (25262912950).

Almost surely, 2100133000311 is an apocalyptic number.

100133000311 is a deficient number, since it is larger than the sum of its proper divisors (918651489).

100133000311 is an equidigital number, since it uses as much as digits as its factorization.

100133000311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 918651488.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 100133000311 its reverse (113000331001), we get a palindrome (213133331312).

The spelling of 100133000311 in words is "one hundred billion, one hundred thirty-three million, three hundred eleven", and thus it is an aban number.

Divisors: 1 109 918651379 100133000311