1001331000112 has 80 divisors (see below), whose sum is σ = 2099013547392. Its totient is φ = 460945612800.

The previous prime is 1001331000083. The next prime is 1001331000113. The reversal of 1001331000112 is 2110001331001.

It is a junction number, because it is equal to n+sod(n) for n = 1001331000092 and 1001331000101.

It is not an unprimeable number, because it can be changed into a prime (1001331000113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25458862 + ... + 25498162.

Almost surely, 2^{1001331000112} is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1001331000112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1049506773696).

1001331000112 is an abundant number, since it is smaller than the sum of its proper divisors (1097682547280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1001331000112 is a wasteful number, since it uses less digits than its factorization.

1001331000112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41366 (or 41360 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1001331000112 its reverse (2110001331001), we get a palindrome (3111332331113).

The spelling of 1001331000112 in words is "one trillion, one billion, three hundred thirty-one million, one hundred twelve", and thus it is an aban number.