100201211111 has 2 divisors, whose sum is σ = 100201211112. Its totient is φ = 100201211110.

The previous prime is 100201211087. The next prime is 100201211171. The reversal of 100201211111 is 111112102001.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100201211111 is a prime.

It is a super-2 number, since 2×100201211111² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100201211092 and 100201211101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100201211171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100605555 + 50100605556.

It is an arithmetic number, because the mean of its divisors is an integer number (50100605556).

Almost surely, 2^100201211111 is an apocalyptic number.

100201211111 is a deficient number, since it is larger than the sum of its proper divisors (1).

100201211111 is an equidigital number, since it uses as much as digits as its factorization.

100201211111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 100201211111 its reverse (111112102001), we get a palindrome (211313313112).

The spelling of 100201211111 in words is "one hundred billion, two hundred one million, two hundred eleven thousand, one hundred eleven".