Base | Representation |
---|---|
bin | 11101001010100110001… |
… | …01011101011010110111 |
3 | 10112210122120001122121212 |
4 | 32211103011131122313 |
5 | 112404321024220434 |
6 | 2044211305432035 |
7 | 132254333450543 |
oct | 16452305353267 |
9 | 3483576048555 |
10 | 1002121320119 |
11 | 356aa73a6117 |
12 | 14227449b61b |
13 | 7366590c94a |
14 | 36708082a23 |
15 | 1b102ae08ce |
hex | e95315d6b7 |
1002121320119 has 2 divisors, whose sum is σ = 1002121320120. Its totient is φ = 1002121320118.
The previous prime is 1002121320113. The next prime is 1002121320121. The reversal of 1002121320119 is 9110231212001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1002121320119 - 28 = 1002121319863 is a prime.
It is a super-2 number, since 2×10021213201192 (a number of 25 digits) contains 22 as substring.
Together with 1002121320121, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1002121320094 and 1002121320103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1002121320113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501060660059 + 501060660060.
It is an arithmetic number, because the mean of its divisors is an integer number (501060660060).
Almost surely, 21002121320119 is an apocalyptic number.
1002121320119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002121320119 is an equidigital number, since it uses as much as digits as its factorization.
1002121320119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 1002121320119 in words is "one trillion, two billion, one hundred twenty-one million, three hundred twenty thousand, one hundred nineteen".
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