Base | Representation |
---|---|
bin | 10010101010101111… |
… | …10000010011011101 |
3 | 221212110120210020212 |
4 | 21111113300103131 |
5 | 131011142200432 |
6 | 4334255022205 |
7 | 503234336132 |
oct | 112527602335 |
9 | 27773523225 |
10 | 10022225117 |
11 | 4283315083 |
12 | 1b3850a965 |
13 | c3949c628 |
14 | 6b10aa589 |
15 | 3d9ced2b2 |
hex | 2555f04dd |
10022225117 has 2 divisors, whose sum is σ = 10022225118. Its totient is φ = 10022225116.
The previous prime is 10022225107. The next prime is 10022225131. The reversal of 10022225117 is 71152222001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8443036996 + 1579188121 = 91886^2 + 39739^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10022225117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10022225092 and 10022225101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10022225107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011112558 + 5011112559.
It is an arithmetic number, because the mean of its divisors is an integer number (5011112559).
Almost surely, 210022225117 is an apocalyptic number.
It is an amenable number.
10022225117 is a deficient number, since it is larger than the sum of its proper divisors (1).
10022225117 is an equidigital number, since it uses as much as digits as its factorization.
10022225117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 23.
Adding to 10022225117 its reverse (71152222001), we get a palindrome (81174447118).
The spelling of 10022225117 in words is "ten billion, twenty-two million, two hundred twenty-five thousand, one hundred seventeen".
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