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10023140013 = 33341046671
BaseRepresentation
bin10010101010110110…
…01111101010101101
3221212112022021020220
421111123033222231
5131011410440023
64334330401553
7503245166355
oct112533175255
927775267226
1010023140013
11428388a497
121b388902b9
13c3972cba3
146b1267b65
153d9e2e3e3
hex2556cfaad

10023140013 has 4 divisors (see below), whose sum is σ = 13364186688. Its totient is φ = 6682093340.

The previous prime is 10023140003. The next prime is 10023140021. The reversal of 10023140013 is 31004132001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10023140013 - 28 = 10023139757 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10023139974 and 10023140001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10023140003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1670523333 + ... + 1670523338.

It is an arithmetic number, because the mean of its divisors is an integer number (3341046672).

Almost surely, 210023140013 is an apocalyptic number.

It is an amenable number.

10023140013 is a deficient number, since it is larger than the sum of its proper divisors (3341046675).

10023140013 is an equidigital number, since it uses as much as digits as its factorization.

10023140013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3341046674.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 10023140013 its reverse (31004132001), we get a palindrome (41027272014).

The spelling of 10023140013 in words is "ten billion, twenty-three million, one hundred forty thousand, thirteen".

Divisors: 1 3 3341046671 10023140013