1002401311 has 4 divisors (see below), whose sum is σ = 1061366112. Its totient is φ = 943436512.

The previous prime is 1002401303. The next prime is 1002401317. The reversal of 1002401311 is 1131042001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1131042001 = 311 ⋅3636791.

It is a cyclic number.

It is not a de Polignac number, because 1002401311 - 2³ = 1002401303 is a prime.

It is a super-3 number, since 3×1002401311³ (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1002401291 and 1002401300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1002401317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29482375 + ... + 29482408.

It is an arithmetic number, because the mean of its divisors is an integer number (265341528).

Almost surely, 2^1002401311 is an apocalyptic number.

1002401311 is a deficient number, since it is larger than the sum of its proper divisors (58964801).

1002401311 is an equidigital number, since it uses as much as digits as its factorization.

1002401311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58964800.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1002401311 is about 31660.7218963813. The cubic root of 1002401311 is about 1000.7997971540.

Adding to 1002401311 its reverse (1131042001), we get a palindrome (2133443312).

The spelling of 1002401311 in words is "one billion, two million, four hundred one thousand, three hundred eleven".