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1002412442021 is a prime number
BaseRepresentation
bin11101001011001000111…
…00000000000110100101
310112211101211212011210112
432211210130000012211
5112410420041121041
62044300225302405
7132264500112464
oct16454434000645
93484354764715
101002412442021
11357136766331
12142335a94a05
13736b101c723
14367349c49db
151b11d448deb
hexe9647001a5

1002412442021 has 2 divisors, whose sum is σ = 1002412442022. Its totient is φ = 1002412442020.

The previous prime is 1002412441999. The next prime is 1002412442023. The reversal of 1002412442021 is 1202442142001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 979676325796 + 22736116225 = 989786^2 + 150785^2 .

It is an emirp because it is prime and its reverse (1202442142001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1002412442021 is a prime.

Together with 1002412442023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1002412442023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501206221010 + 501206221011.

It is an arithmetic number, because the mean of its divisors is an integer number (501206221011).

Almost surely, 21002412442021 is an apocalyptic number.

It is an amenable number.

1002412442021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002412442021 is an equidigital number, since it uses as much as digits as its factorization.

1002412442021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1024, while the sum is 23.

Adding to 1002412442021 its reverse (1202442142001), we get a palindrome (2204854584022).

The spelling of 1002412442021 in words is "one trillion, two billion, four hundred twelve million, four hundred forty-two thousand, twenty-one".