Base | Representation |
---|---|
bin | 10010101011000000… |
… | …01001001100100111 |
3 | 221212121201111212112 |
4 | 21111200021030213 |
5 | 131012223033411 |
6 | 4334414111235 |
7 | 503262125423 |
oct | 112540111447 |
9 | 27777644775 |
10 | 10024424231 |
11 | 4284587328 |
12 | 1b391ab51b |
13 | c39a8c593 |
14 | 6b14bdb83 |
15 | 3da0d4b8b |
hex | 255809327 |
10024424231 has 2 divisors, whose sum is σ = 10024424232. Its totient is φ = 10024424230.
The previous prime is 10024424227. The next prime is 10024424233. The reversal of 10024424231 is 13242442001.
It is a strong prime.
It is an emirp because it is prime and its reverse (13242442001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10024424231 - 22 = 10024424227 is a prime.
It is a super-2 number, since 2×100244242312 (a number of 21 digits) contains 22 as substring.
Together with 10024424233, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 10024424197 and 10024424206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10024424233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012212115 + 5012212116.
It is an arithmetic number, because the mean of its divisors is an integer number (5012212116).
Almost surely, 210024424231 is an apocalyptic number.
10024424231 is a deficient number, since it is larger than the sum of its proper divisors (1).
10024424231 is an equidigital number, since it uses as much as digits as its factorization.
10024424231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 10024424231 its reverse (13242442001), we get a palindrome (23266866232).
The spelling of 10024424231 in words is "ten billion, twenty-four million, four hundred twenty-four thousand, two hundred thirty-one".
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