10025117 has 2 divisors, whose sum is σ = 10025118. Its totient is φ = 10025116.

The previous prime is 10025107. The next prime is 10025123. The reversal of 10025117 is 71152001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6661561 + 3363556 = 2581^2 + 1834^2 .

It is an emirp because it is prime and its reverse (71152001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10025117 - 2⁴ = 10025101 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10025095 and 10025104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10025107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012558 + 5012559.

It is an arithmetic number, because the mean of its divisors is an integer number (5012559).

Almost surely, 2^10025117 is an apocalyptic number.

It is an amenable number.

10025117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10025117 is an equidigital number, since it uses as much as digits as its factorization.

10025117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 70, while the sum is 17.

The square root of 10025117 is about 3166.2465159870. The cubic root of 10025117 is about 215.6236946501.

Adding to 10025117 its reverse (71152001), we get a palindrome (81177118).

The spelling of 10025117 in words is "ten million, twenty-five thousand, one hundred seventeen".