Base | Representation |
---|---|
bin | 10010101011101010… |
… | …11101110000011111 |
3 | 221220000020110212102 |
4 | 21111311131300133 |
5 | 131020140412341 |
6 | 4335133555315 |
7 | 503360464532 |
oct | 112565356037 |
9 | 27800213772 |
10 | 10030013471 |
11 | 4287754635 |
12 | 1b3b045b3b |
13 | c3ac9861a |
14 | 6b2136a19 |
15 | 3da83ac9b |
hex | 255d5dc1f |
10030013471 has 2 divisors, whose sum is σ = 10030013472. Its totient is φ = 10030013470.
The previous prime is 10030013437. The next prime is 10030013473. The reversal of 10030013471 is 17431003001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10030013471 - 230 = 8956271647 is a prime.
It is a super-3 number, since 3×100300134713 (a number of 31 digits) contains 333 as substring.
Together with 10030013473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10030013473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015006735 + 5015006736.
It is an arithmetic number, because the mean of its divisors is an integer number (5015006736).
Almost surely, 210030013471 is an apocalyptic number.
10030013471 is a deficient number, since it is larger than the sum of its proper divisors (1).
10030013471 is an equidigital number, since it uses as much as digits as its factorization.
10030013471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 10030013471 its reverse (17431003001), we get a palindrome (27461016472).
The spelling of 10030013471 in words is "ten billion, thirty million, thirteen thousand, four hundred seventy-one".
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