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1003152132055 = 5200630426411
BaseRepresentation
bin11101001100100001000…
…01101100011111010111
310112220022101201022202201
432212100201230133113
5112413423421211210
62044501451345331
7132322021301263
oct16462041543727
93486271638681
101003152132055
11357486254407
12142501752247
137379b347538
14367a4d310a3
151b16335b53a
hexe99086c7d7

1003152132055 has 4 divisors (see below), whose sum is σ = 1203782558472. Its totient is φ = 802521705640.

The previous prime is 1003152132043. The next prime is 1003152132067. The reversal of 1003152132055 is 5502312513001.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1003152132043) and next prime (1003152132067).

It is not a de Polignac number, because 1003152132055 - 229 = 1002615261143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100315213201 + ... + 100315213210.

It is an arithmetic number, because the mean of its divisors is an integer number (300945639618).

Almost surely, 21003152132055 is an apocalyptic number.

1003152132055 is a deficient number, since it is larger than the sum of its proper divisors (200630426417).

1003152132055 is an equidigital number, since it uses as much as digits as its factorization.

1003152132055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200630426416.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 1003152132055 its reverse (5502312513001), we get a palindrome (6505464645056).

The spelling of 1003152132055 in words is "one trillion, three billion, one hundred fifty-two million, one hundred thirty-two thousand, fifty-five".

Divisors: 1 5 200630426411 1003152132055