Base | Representation |
---|---|
bin | 1001000111111101010100… |
… | …0000100110010100100011 |
3 | 1022112002011210102020221221 |
4 | 2101333111000212110203 |
5 | 2303332144004341011 |
6 | 33200441340555511 |
7 | 2053545204611140 |
oct | 221772500462443 |
9 | 38462153366857 |
10 | 10032322340131 |
11 | 3218758467613 |
12 | 11603b8552b97 |
13 | 57a0756b8080 |
14 | 2697d1b7d3c7 |
15 | 125e6c8a2971 |
hex | 91fd5026523 |
10032322340131 has 64 divisors (see below), whose sum is σ = 13120968591360. Its totient is φ = 7443806423040.
The previous prime is 10032322340119. The next prime is 10032322340167. The reversal of 10032322340131 is 13104322323001.
It is not a de Polignac number, because 10032322340131 - 211 = 10032322338083 is a prime.
It is a super-2 number, since 2×100323223401312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10032322340096 and 10032322340105.
It is not an unprimeable number, because it can be changed into a prime (10032322340531) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1794367146 + ... + 1794372736.
It is an arithmetic number, because the mean of its divisors is an integer number (205015134240).
Almost surely, 210032322340131 is an apocalyptic number.
10032322340131 is a deficient number, since it is larger than the sum of its proper divisors (3088646251229).
10032322340131 is a wasteful number, since it uses less digits than its factorization.
10032322340131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9604.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 10032322340131 its reverse (13104322323001), we get a palindrome (23136644663132).
The spelling of 10032322340131 in words is "ten trillion, thirty-two billion, three hundred twenty-two million, three hundred forty thousand, one hundred thirty-one".
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