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100340000213 is a prime number
BaseRepresentation
bin101110101110010111…
…0101110010111010101
3100120222212102010212012
41131130232232113111
53120444020001323
6114032350234005
710151342633525
oct1353456562725
9316885363765
10100340000213
1139610350312
12175437b5905
1396010a41bb
144bdc287685
152923eea678
hex175cbae5d5

100340000213 has 2 divisors, whose sum is σ = 100340000214. Its totient is φ = 100340000212.

The previous prime is 100340000209. The next prime is 100340000221. The reversal of 100340000213 is 312000043001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65526784324 + 34813215889 = 255982^2 + 186583^2 .

It is an emirp because it is prime and its reverse (312000043001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100340000213 - 22 = 100340000209 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100340000713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50170000106 + 50170000107.

It is an arithmetic number, because the mean of its divisors is an integer number (50170000107).

Almost surely, 2100340000213 is an apocalyptic number.

It is an amenable number.

100340000213 is a deficient number, since it is larger than the sum of its proper divisors (1).

100340000213 is an equidigital number, since it uses as much as digits as its factorization.

100340000213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 100340000213 its reverse (312000043001), we get a palindrome (412340043214).

The spelling of 100340000213 in words is "one hundred billion, three hundred forty million, two hundred thirteen", and thus it is an aban number.