Base | Representation |
---|---|
bin | 10010101100001001… |
… | …10101000100011101 |
3 | 221220021211002202111 |
4 | 21112010311010131 |
5 | 131022203303432 |
6 | 4335400154021 |
7 | 503436641122 |
oct | 112604650435 |
9 | 27807732674 |
10 | 10034041117 |
11 | 4289a55671 |
12 | 1b40468911 |
13 | c3ba78949 |
14 | 6b28a4749 |
15 | 3dad84347 |
hex | 25613511d |
10034041117 has 2 divisors, whose sum is σ = 10034041118. Its totient is φ = 10034041116.
The previous prime is 10034041109. The next prime is 10034041163. The reversal of 10034041117 is 71114043001.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10029822201 + 4218916 = 100149^2 + 2054^2 .
It is an emirp because it is prime and its reverse (71114043001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10034041117 - 23 = 10034041109 is a prime.
It is a super-2 number, since 2×100340411172 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10034041217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017020558 + 5017020559.
It is an arithmetic number, because the mean of its divisors is an integer number (5017020559).
Almost surely, 210034041117 is an apocalyptic number.
It is an amenable number.
10034041117 is a deficient number, since it is larger than the sum of its proper divisors (1).
10034041117 is an equidigital number, since it uses as much as digits as its factorization.
10034041117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 22.
Adding to 10034041117 its reverse (71114043001), we get a palindrome (81148084118).
The spelling of 10034041117 in words is "ten billion, thirty-four million, forty-one thousand, one hundred seventeen".
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