100352050031 has 2 divisors, whose sum is σ = 100352050032. Its totient is φ = 100352050030.

The previous prime is 100352049949. The next prime is 100352050033. The reversal of 100352050031 is 130050253001.

It is a strong prime.

It is an emirp because it is prime and its reverse (130050253001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100352050031 - 2¹⁴ = 100352033647 is a prime.

It is a super-2 number, since 2×100352050031² (a number of 23 digits) contains 22 as substring.

Together with 100352050033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100352049985 and 100352050012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100352050033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50176025015 + 50176025016.

It is an arithmetic number, because the mean of its divisors is an integer number (50176025016).

Almost surely, 2^100352050031 is an apocalyptic number.

100352050031 is a deficient number, since it is larger than the sum of its proper divisors (1).

100352050031 is an equidigital number, since it uses as much as digits as its factorization.

100352050031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 20.

The spelling of 100352050031 in words is "one hundred billion, three hundred fifty-two million, fifty thousand, thirty-one".