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100401304235 = 5199910045153
BaseRepresentation
bin101110110000001100…
…0100101001010101011
3100121011010202201011112
41131200120211022223
53121110213213420
6114042420220535
710153016001461
oct1354030451253
9317133681145
10100401304235
1139641a119a1
121756023a74b
1396109b987b
144c06484831
1529295a98c5
hex17606252ab

100401304235 has 8 divisors (see below), whose sum is σ = 120541848000. Its totient is φ = 80280854784.

The previous prime is 100401304229. The next prime is 100401304307. The reversal of 100401304235 is 532403104001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100401304235 - 226 = 100334195371 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100401304235.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5012582 + ... + 5032571.

It is an arithmetic number, because the mean of its divisors is an integer number (15067731000).

Almost surely, 2100401304235 is an apocalyptic number.

100401304235 is a deficient number, since it is larger than the sum of its proper divisors (20140543765).

100401304235 is a wasteful number, since it uses less digits than its factorization.

100401304235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10047157.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 100401304235 its reverse (532403104001), we get a palindrome (632804408236).

The spelling of 100401304235 in words is "one hundred billion, four hundred one million, three hundred four thousand, two hundred thirty-five".

Divisors: 1 5 1999 9995 10045153 50225765 20080260847 100401304235