10040143117 has 2 divisors, whose sum is σ = 10040143118. Its totient is φ = 10040143116.

The previous prime is 10040143081. The next prime is 10040143123. The reversal of 10040143117 is 71134104001.

It is a happy number.

10040143117 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9930919716 + 109223401 = 99654^2 + 10451^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10040143117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10040141117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020071558 + 5020071559.

It is an arithmetic number, because the mean of its divisors is an integer number (5020071559).

Almost surely, 2^10040143117 is an apocalyptic number.

It is an amenable number.

10040143117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10040143117 is an equidigital number, since it uses as much as digits as its factorization.

10040143117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 336, while the sum is 22.

Adding to 10040143117 its reverse (71134104001), we get a palindrome (81174247118).

The spelling of 10040143117 in words is "ten billion, forty million, one hundred forty-three thousand, one hundred seventeen".